A. Ocean tides are waves that have a period of 12 hours, an amplitude (in some p
ID: 1621852 • Letter: A
Question
A. Ocean tides are waves that have a period of 12 hours, an amplitude (in some places) of 1.50 m, and a speed of 787 km/hr. What is the distance between adjacent crests of these waves? (Give answer to the nearest km/hr)
B. A transverse wave is traveling on a string stretched along the horizontal x-axis. The equation for the vertical displacement y of the string is given by y = (1.6 x 10-3)cos[(12x - 55t)], where all quantities are in SI units. What is the maximum speed of a particle of the string? (Give your answer to the nearest 0.01 m/s).
Explanation / Answer
A)Given,
Time, T = 12 hours
Speed, V= 787 km/ hr
Wavelength, = V x T = 787 x 12 = 9444 km
Therefore, the distance between adjacent crests of these waves = 9444 km
B) From given equation for the vertical displacement,
Amplitude, A = 1.6 x 10-3
Angular velocity, = 55
Therefore, Vmax = A = 0.0016 x 55 = 0.276 m/s