The moment of inertia of a pulley wheel (radius=0.40 m) is 10.0 kg-m^2. Find the

Question

The moment of inertia of a pulley wheel (radius=0.40 m) is 10.0 kg-m^2. Find the angular acceleration of the wheel caused by a 20.0 kg mass sliding down an incline, if the frictional force between the mass and the incline is 50 N. The angle of the incline is 37 degrees. The moment of inertia of a pulley wheel (radius=0.40 m) is 10.0 kg-m^2. Find the angular acceleration of the wheel caused by a 20.0 kg mass sliding down an incline, if the frictional force between the mass and the incline is 50 N. The angle of the incline is 37 degrees.

Explanation / Answer

since torque is given by

T=rf

where f=frictional force

T=50*0.4=20 kg-m2

since

T=I*alpha

angular acceleration

alpha=T/I=20/10

alpha =2 rad/sec2

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