Problem 6 Two thin lenses with a focal length of magnitude 18.0 cm, the first di

Question

Problem 6 Two thin lenses with a focal length of magnitude 18.0 cm, the first diverging and the second converging, are located 13.5 cm apart. An object 2.40 mm tall is placed 30.0 cm to the left of the first (diverging) lens. You may want to review (D ages 1128-1136) For related problem-solving tips and strategies, you may want to view a Video Tutor Solution of An image of an image Part A How far from this first lens is the final image formed? cm. Submit My Answers Give U Incorrect: Try Again: 4 attempts remaining Part B ls the final image real or virtual? rea Submit My Answers Give Up Correct 0 so the final image is real. Part C What is the height of the final image? Submit My Answers Give U incorrect; Try Again: 3 attempts remaining Part D ls it erect or inverted? inverted Submit My Answers Give Up

Explanation / Answer

f is the focal length of combination

1/f = (1/f1) + (1/f2) - d/(f1f2)

where, f1 = -18cm and f2 = +18cm

1/f = (1/-18) +(1/+18) - 13.5/(-18*18) = 13.5/324

f = 324/13.5 = 24 cm

Part A

v = uf/(u - f) = 30*24/(30 - 24) = 30*24/6 = 120 cm

Part B

Image is real because,

v is positive and is on other side of lens combination.

Part C

m = -v/u = -120/30 = -4

The height of the image is 4*2.40 = 9.6 mm

Part D

Image is erected.

because the value of m is negative.

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