Please I need help with Part A...anyone? In its resting state, the member surrou
ID: 1631983 • Letter: P
Question
Please I need help with Part A...anyone?
In its resting state, the member surrounding a neuron is permeable to potassium ions but only slightly permeable to sodium ions. Thus, positive K ions can flow through the concentration, but Na ions cannot as quickly. This leads to an excess of Na ions outside of the cell. If the square outside the cell. If the space outside the cell is defined as zero electric potential, then the electric potential of the interior of the cell is negative. This resting potential is typically about -80 m V. A schematic of this situation is shown in the figure. (Figure 1) In response to an electrical stimulus, certain channels in the membrane can become permeable to NA ions. Due to concentration gradient, Na ions rush into the cell and the interior of the cell reaches an electronic potential of about 40 m V. This process is termed depolarization. In response to depolarization, the membrane again becomes less permeable to Na ions, and k ions flow out of the interior of the cell through channels established by the positive electric potential inside of the cell. This is then reestablishing the resting potential. This is termed repolarization. Only a small percentage of the available Na and K ions participate in each depolarization/repolarization cycle, so the cell can respond to many stimuli in successions without depleting its "stock" of available Na and K ions. A graph of an electric potential inside a cell vs. time is shown in the next figure (Figure 2) for a single depolarization/repolarization cycle. During the resting phase, what is the electric potential energy of a typical Na ion outside of the cell? This question will be shown after you complete previous question(s).Explanation / Answer
(A)
0 meV
Because it does not have electric potential outside of the cell membrane.
U = qV = eV