Coulomb\'s Law describes the force between two (and only two!) charged objects.
ID: 1636766 • Letter: C
Question
Coulomb's Law describes the force between two (and only two!) charged objects. Suppose Object 1 has a charge of +1.53 mu C and Object 2 has a charge of +14.8 mu C Object 2 is located a distance of 0.03840 m to the right of Object 1 (Yes- please break down and draw a quick sketch!). What is the magnitude and direction of the electrical force on Object 2 due to Object 1? to the left to the right What is the magnitude and direction of the electrical force on Object 1 due to Object 2? to the right to the left You now move Object 2 such that it is located a distance of 0.07680 m to the right of Object 1 (twice the distance as before). What is the magnitude and direction of the electrical force on Object 2 due to Object 1? to the left to the right The new force on Object 1 due to Object 2 (at a separation of 0.07680 m) is _____ times the original force on Object 1 due to Object 2 (at a separation of 0.03840 m)? (Provide a numerical answer fill in the blank.)Explanation / Answer
Electric force by object 2 on object 1 = kq1q2 / r^2
= 9*10^9 * 1.53*14.8*10^-12 / 0.0348^2
= 168.28N ( to the left )
Electric force by object 1 on objecct 2 = 168.28 N (to the right)
since the distance is doubled , The magnitude of force will be quadrupled now
new force = (4*168.28) = 673.17 N and the direction remains the same