Please help me with this ASAP, ty. The figure shows the trajectory of a golf bal
ID: 1639274 • Letter: P
Question
Please help me with this ASAP, ty.
The figure shows the trajectory of a golf ball in projectile motion over level ground. The time t0 = 0 s corresponds to the moment just after the ball is launched from position x0 = 0 m, y0 = 0 m. Its initial velocity (launch velocity) is v0. Two other points along the trajectory are indicated in the figure. At time t1 (with velocity v1), the ball reaches the peak of its trajectory. Its position at this moment is denoted by (x1, y1) = (x1, ymax), since it is at its maximum height. At time t2 (with velocity v2), just before the ball touches the ground again, its position is (x2, y2) = (xmax, y2), since it is at its maximum horizontal range.
peak height yman initial position 1. [1pt] Which of the statement are true? E g., enter AB. A. Ivo v2 B. vo,y V2,y C. vox VI.x D. ao, y a1,y a2,y E. vo.x VI.x F. vo, y V2, y G. a1,y H. Ivo V2 Answcr Submit All Answers 2. 11pt Assume an initial speed of 17 m/s, at an angle of 59.9° with respect to the positive xaxis. Find the velocity at time to; enter the x component, then the y component. Answcr 1 of 2: Answer 2 of 2: Submit All Answers 3. [1pt] What are the xy components of the acceleration a to? Answcr 1 of 2: Answer 2 of 2: Submit All Answers 4. [1 pt] What are the xy components of the velocity at t? Answcr 1 of 2: Answer 2 of 2: Submit All Answers 5. [1pt] What are the xy components of the acceleration a t? Answcr 1 of 2: Answer 2 of 2: Submit All Answers 6. 11pt Calculate the amount of time the ball spends in the air. Answcr Submit All AnswersExplanation / Answer
1.
C, D, F, H are true. so answer is CDFH.
2.
x component = 17 * cos(59.9) = 8.53 m/s
y component = 17 *sin (59.9) = 14.71 m/s
3.
ax0 =0 m/s2
ay0 = -9.8 m/s2
4.
vx1 = vx0 = 8.53 m/s
vy1 = 0 m/s
5.
ax1 =ax0 = 0 m/s2
ay1 = ay0 = -9.8 m/s2
6.
time of flight , t = (2v0 sin theta) / g = ( 2* 17 * sin(59.9)) / 9.8
t = 3.0 s