Positive point charges q = +8.25 mu C and q\' = +3.75 mu C are moving relative t

Question

Positive point charges q = +8.25 mu C and q' = +3.75 mu C are moving relative to an observer at point P, as shown in the following figure. The distance d is 0.125 m, v = 4.20 times 10^6 m/s, and v' = 9.30 times 10^6 m/s. (a) When the two charges are at the locations shown in the figure, what are the magnitude and direction of the net magnetic field they produce at point P? magnitude 4.45E-4 T direction (b) What are the magnitude and direction of the electric and magnetic forces that each charge exerts on the other. on charge q: electric force magnitude N direction magnetic force magnitude N direction on charge q': electric force magnitude N direction magnetic force magnitude N direction What is the ratio of the magnitude of the electric force to the magnitude of the magnetic force? F_C/F_B = (c) If the direction of v is reversed, so both charges are moving in the same direction, what are the magnitude and direction of the magnetic forces that the two charges exert on each other? on charge q: magnetic force magnitude N direction on charge q': magnetic force magnitude N direction

Explanation / Answer

Fb = (u/4*pi)qq'vv'/r^2 = 10^-7*8.25*3.75*10^-12*4.2*9.3*10^12/0.25^2 = 1.93347*10^-3 N

Force on upper charge points up and lower down

Fc = kqq'/r^2 = 9*10^9*8.25*3.75*10^-12/0.25^2 = 4.455 N

Fc/Fb = 2304.15

c) direction is reversed, magnitude remains same.

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