Conduction electrons move to the right in a certain wire. This indicates that th

Question

Conduction electrons move to the right in a certain wire. This indicates that the conventional current density points left but the direction of the electric field is unknown the conventional current density points right and the electric filed points left the conventional current density points left and the electric filed points right. the conventional current density and the electric filed both point right the conventional current density and electric field both left. None of the above The time constant RC has units of. second/farad second/ohm second second/watt none of these In the circuit shown, there will be a non-zero reading in galvanometer G (a galvanometer is a device that can measure very small currents): only just after S is opened or closed only while S is kept closed only just after S is opened only just after S is closed None of the above Two point charges are arranged as shown. In which region could a third charge +1 C be placed so that the net electrostatic force on it is zero? II only I and III only III only I and II only I only

Explanation / Answer

problem :2

the units of time constant is seconds

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(3) ans

the galavanometer shown non-zero reading in circuit it works only while switch is kept closed

because the current passing in the circuit in closed condition only

(4) ans

Given that

charge q1=2C

charge q2=-4 c

now we find the thrd charge placed region

distance x=r/(-4/2)^1/2-1

=r/-1.414-1

=-0.4143 r

the third charge is placed in region 1 only

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