Part A One point charge +Q is placed at the center of a square, and a second poi

Question

Part A One point charge +Q is placed at the center of a square, and a second point charge -Q is placed at the upper-left corner of the square. It is observed that an electrostatic force of magnitude 2.0 N acts on the positive charge at the center. Now a third charge -Q is placed at the lower-left corner of the square, as shown in the figure. What is the magnitude of the net force that acts on the center charge now? The figure shows one positive charge labeled + Q placed at the center of a square and two negative charges labeled -Q placed at the upper left and the bottom left corners of the square.

A)0.0 N

B)2.8 N

C)5.3 N

d)4.0 N

Explanation / Answer

Forces due to corner charges of a square acts diagonally and diagonals of square intersect at 90 degree.

So the resultant of two such forces at 90 degree

Fnet = sqrt(2^2+2^2)

= 2.8 N

option B is correct

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