Initially, three identical metal spheres are far apart so there is no interactio
ID: 1651473 • Letter: I
Question
Initially, three identical metal spheres are far apart so there is no interaction: sphere A has charge qA = 5.56 C, sphere B has charge qB = -6.93 C and sphere C is neutral.
Now: - First sphere A and sphere B are brought together until they touch, and then separated so they are very far apart again.
- Next, sphere B and sphere C are brought together until they touch, and then separated so they are very far apart again.
- Finally: sphere C and sphere A together are brought together until they touch, and then separate so they are very far apart again.
Calculate the final charge on sphere A, in C.
Explanation / Answer
after First sphere A and sphere B are brought together
charge on A and B = (5.56 - 6.93)/2 = -0.685
after sphere B and sphere C are brought together
charge on B and C = (-0.685 + 0 )/2 = - 0.3425
after sphere C and sphere A together are brought together
charge on C and A = (-0.3425 - 0.685)/2 = - 0.51375
final charge on sphere A = - 0.514 C.