Assignment 1 Problem 25.35 « previous 9 of 11 next » Problem 25.35 Part A What i

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Assignment 1

Problem 25.35

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Problem 25.35

Part A

What is the magnitude of the force F  on the -10 nC charge in the figure(Figure 1) ?

Express your answer using two significant figures.

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Part B

What is the direction of the force F  on the -10 nC charge in the figure? Give your answer as an angle measured cw or ccw (specify which) from the +x-axis.

Express your answer using two significant figures. Enter positive value if the angle is counterclockwise and negative value if the angle is clockwise.

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Figure 1 of 1

Problem 25.35

Part A

What is the magnitude of the force F  on the -10 nC charge in the figure(Figure 1) ?

Express your answer using two significant figures.

F=   N  

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Part B

What is the direction of the force F  on the -10 nC charge in the figure? Give your answer as an angle measured cw or ccw (specify which) from the +x-axis.

Express your answer using two significant figures. Enter positive value if the angle is counterclockwise and negative value if the angle is clockwise.

=   

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Figure 1 of 1

15 nC 5.0 nC 3.0 cm 1.0 cm -10 nC

Explanation / Answer

Force on -10nC due to +15nC:

F1 = (9*10^9*(15*10^-9)*(10*10^-9)/(0.03^2 + 0.01^2)))*( -3/sqrt(3^2 + 1^2) i + 1/sqrt(3^2+1^2) j )

= 0.00135*(-0.949 i + 0.316 j)

Similalrly force on -10nC due to -5nC:

F2 =  (9*10^9*(15*10^-9)*(5*10^-9)/(0.03^2 + 0.01^2)))*( - j )

= -0.000675 j

So, net force on it :

Fnet = F1 + F2

= 0.00135*(-0.949 i + 0.316 j) + ( -0.000675 j )

= -0.00128 i - 0.000248 j

So, magnitude = sqrt(0.00128^2 + 0.000248^2)

= 0.001305 N

= 1.31*10^-3 N

b)

direction = atan(0.000248/0.00128)

= 90 + 11 deg = 101 deg with respect to +x axis

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