QUESTION 2 A car drives at 20 m/s on a flat, circular trock with radius 200 m. I

Question

QUESTION 2 A car drives at 20 m/s on a flat, circular trock with radius 200 m. If the car has a mass of 800 kg, what is the force of friction between the track and the car's tires? Hint iR is the frictional force that causes the car's centripetal acceleration O a 80 N Ob.2N O c. 1800 N Od.800 N QUESTION 3 Acar drives at 20m/s on afiat, ci iar track with radus 200m. cars tires and the road? the car has a mass of 800kg, what is the coofficient of friction between the C b.0.0 c.0.2 Ciek Save and Submi to save arnd suhmit. Click Save All Anexers to sove all anmpers Save All Answe 20 3 4 8

Explanation / Answer

Here centrepetal force is provided by friction,

umg = mv^2/r

u = v^2/rg

= 20^2/(200*9.8)

= 0.2 answer

option c is correct

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