QUESTIONS tape for a glider on an air track. The spark pits are numbered from ze
ID: 1659844 • Letter: Q
Question
QUESTIONS tape for a glider on an air track. The spark pits are numbered from zero to 15. Alongside the tape is a distance number zero was made at t-0 sec. Displacements are measured from the starting point (t 0). The spark rate for this tape was 10 sparks/sec. Work this problem in cm/s and measure you positions to the 12 13 14 a) Compute the average acceleration of the glider between spark pit 5 and spark pit 9. b) Compute the average acceleration ofthe glider as it moves from x-5.5 can to x-10.5 cm.Explanation / Answer
a)
Period between sparks = 0.1 sec (frequency = 10 Hz).
the average velocity between points 5 and 6
initial velocity (u).
u = s / t = (0.021 – 0.015) / 0.1 = 0.06 m/s
the average velocity between points 8 and 9
final velocity v
v = s / t = (0.045 – 0.036) / 0.1 = 0.09 m/s
This will be 3 time intervals (sparks) (3 x 0.1 = 0.3 seconds).
t = 0.3 sec
a = (v –u) / t = (0.09 – 0.06) / 0.3
a = 0.1 m/s^2
----------------------------------------------------------------------------------------------------------------
b)
x = 5.5 cm is at spark pit 10 and x = 10.5 at spark pit 14
To calculate the average acceleration of the glider between spark pit 10 and spark pit 14.
Period = 0.1 sec (frequency = 10 Hz).
the average velocity between points 10 and 11
initial velocity (u).
u = s / t = (0.066– 0.055) / 0.1 = 0.11 m/s
the average velocity between points 13 and 14
final velocity v
v = s / t = (0.105– 0.09) / 0.1 = 0.15 m/s
This will be 5 time intervals (sparks) (5 x 0.1 = 0.5 seconds).
t = 0.5 sec
a = (v –u) / t = (0.15– 0.11) / 0.5
a = 0.08 m/s^2