Two protons are 2.2 fm apart. Part A What is the magnitude of the electric force

Question

Two protons are 2.2 fm apart. Part A What is the magnitude of the electric force on one proton due to the other proton? Express your answer to two significant figures and include the appropriate units 0 PeValue Units Submit X Incorrect, Try Again; 5 attempts remaining Part B What is the magnitude of the gravitational force on one proton due to the other proton? Express your answer to two significant figures and include the appropriate units. Fe= V Units atue Submit Part C What is the ratio of the electric force to the gravitational force? Express your answer using two significant figures. 0

Explanation / Answer

Given

two protons are separated by r = 2.2 fm = 2.2*10^-15 m

and we know the charge of proton is q = 1.6*10^-19 C

from Coulomb's law F = kq1*q2/r^2

Part A

here F = kq^2/r^2

F_E = 9*10^9*(1.6*10^-19)^2/(2.2*10^-15)^2 N = 47.6033 N

so the magnitude of the electric force on one proton due to the other proton is Fe = 47.6033 N

Part B

the gravitational force of attraction on one proton due to the other proton is F = G*m1*m2/r^2

G = 6.674*10^-11 N m2 /kg^2

and mass of proton is 1.6726*10^-27 kg

F_G = (6.674*10^-11*1.6726*10^-27*1.6726*10^-27)/(2.2*10^-15)^2 N

F_G = 3.8577*10^-35 N

Part C

Ratio of electric force to the gravitational force is  

F_E /F_G = (47.6033)/(3.8577*10^-35)

F_E/F_G = 1.233981*10^36

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