Need help with this question please explain as im lost, thnak you. A student dri
ID: 1661663 • Letter: N
Question
Need help with this question please explain as im lost, thnak you.
A student drives a moped along a straight road as described by the velocity versus time graph in the figure. The divisions along the hcrizontal axis represent 2.0 s and the divisions along the vertical axis represent 4.0 m/s. Sketch this graph in the middle of a sheet of graph paper. (Do this on paper. You will need it to do part (a) and (b).) middle or on paper ou m/s) t (s) () Directy abave yaur graah, skesch a graph of the peaition versus time, aligning the time coordinates of the two graphs. (Do this on paper. Your instructor may ask you so tum in your wark.) for all points of iniflection. (Dtis on paper. Your instructor may ask you to turn in (b) Sketch a greph of the acceleration versus time directly below the velocity-time graph, aain eligning the time cvord netes. On each graph, show the numerical values of x and your work (c) Whet lis the acce eration at t-12.0? m/s2 (d) Find the position (relative to the starting point) at t = 12.0 s. (e) What is the maped's finel position att 18.0 s?Explanation / Answer
a) position vs time graph can be obtained by integrating the given graph with respect to time.(area under the graph)
b) Acceleration vs time graph can be obtained by differentiating the given graph at each point with respect to time because acceleration, a = dv/dt.
c) a t=12 = dv/dt (at t=12sec) = -(16-8)/(2-0) = -4m/s2
d) Postion at t=12sec = Area under the grapgh upto 12 seconds = (0.5 * 6 *16 + 4*16 + (2*4 + 0.5 *2* 8) ) = 128m