Question
I tried to look the answer from here, but they did not giveany answer. So, I really need help!!T_T Q) Which will give the greater improvement in the efficiencyof a Carnot engine, a 10C increase in the high-temperaturereservoir, or a 10C decrease in the low-temperature reservoir?Explain. Thank you. I tried to look the answer from here, but they did not giveany answer. So, I really need help!!T_T Q) Which will give the greater improvement in the efficiencyof a Carnot engine, a 10C increase in the high-temperaturereservoir, or a 10C decrease in the low-temperature reservoir?Explain. Thank you.
Explanation / Answer
The greater improvement in the efficiency of a Carnot engineby a 10C decrease in the low-temperature reservoir than a 10Cincrease in the high-temperature reservoir. Note: ----- Let hot body temperature T = 373 K and cold bodytemperature T ' = 273 K then efficiency n = 1 - ( T ' / T ) = 0.26809 = 26.809% After a 10C increase in the high-temperature reservoir i.e., T= 373 + 10 = 383 Then efficiency n ' = 1-( T ' / T ) = 1-( 273/383) =0.2872 = 28.72 % After 10C decrease in the low-temperature reservoir i.e., T '= 273-10 = 263 then efficiency n " = 1-( T ' / T ) = 1-( 263/373) = 0.2949 =29.49 % ( n ' - n ) < ( n" - n )