The weight of a 0.6 kg object of charge Q is just balanced byanother object of e

Question

The weight of a 0.6 kg object of charge Q is just balanced byanother object of equal but opposite charge fixed to a support 106cm above it. What is the magnitude of the charge Q (in C)?[Note that 1 C=1x10-6C.] I understand the equation F= (k|q||q)|/(r^2) but I do notknow how to find F to solve for q.

The weight of a 0.6 kg object of charge Q is just balanced byanother object of equal but opposite charge fixed to a support 106cm above it. What is the magnitude of the charge Q (in C)?[Note that 1 C=1x10-6C.] I understand the equation F= (k|q||q)|/(r^2) but I do notknow how to find F to solve for q.

Explanation / Answer

where repulsive force balances the weight So, force F = weight = mg = 0.6 kg * 9.8 m / s ^ 2= 5.88N distance r= 106 cm = 1.06 m we know F = K qq / r ^ 2 from tis charge   q = r [ F / K ] where K = 8.99 * 10 ^ 9 N m ^ 2/ C ^ 2 plug the values wgeet q = 2.71 * 10 ^ -5 C                                     = 27.1 * 10 ^ -6 C = 27.1 C

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