Dipole in a Field An electric dipole, consistingof charges of magnitude 4.40 nC

Question

Dipole in a Field An electric dipole, consistingof charges of magnitude 4.40 nC separatedby 7.80 µm, is in an electric fieldof strength 1200 N/C. (a) What is the magnitude of the electricdipole moment?
1 C·m
(b) What is the difference between the potential energiescorresponding to dipole orientations parallel to and antiparallelto the field?
2 J (a) What is the magnitude of the electricdipole moment?
1 C·m
(b) What is the difference between the potential energiescorresponding to dipole orientations parallel to and antiparallelto the field?
2 J

Explanation / Answer

(a)           Dipole moment p = q*l                                      = 4.4*10-9C * 7.8*10-6m                                      = 34.32 * 10-15C.m (b)          thedifference between the potential energies corresponding to dipoleorientations parallel to and antiparallel to the field is 2pE= (2)(34.32 * 10-15C.m)(1200N/C)                  =82.4*10-12J                 = 82.4pJ

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