A nonconducting solid sphere of radius 2.80cm carries a uniformly distributed po

Question

A nonconducting solid sphere of radius 2.80cm carries a uniformly distributed positive charge of7.20×10-9 C. Calculate the magnitude of theelectric field at a point 1.50 cm away from the center of thesphere.

Calculate the magnitude of the electric field at a point 3.70 cmaway from the center of the sphere.

Assume that the sphere is conducting. Calculate the magnitude ofthe electric field at a point 1.50 cm away from the center of thesphere.

Calculate the magnitude of the electric field for the conductingsphere at a point 3.70 cm away from the center of the sphere.

Explanation / Answer

You should use Gauss's Law to answer these questions. First, you need to get the equation for Electric field whenyou are within the non-conducting sphere. The equation for that is: E = qr/(4oR3) where r isequal to the radius of the defined radius and R is the radius ofthe sphere. E = 7.2 * 10-9C * 0.015m/4 * 8.85*10-12F/m * .0283 = 44238N/C To calculate the electric field outside the sphere, you woulduse this equation: E = q/(4or2) 7.2 * 10-9C/4 * 8.85* 10-12F/m *.0372 = 47290N/C The electric field within a conducting sphere is 0N/C. The electric field outside of a conducting sphere is the sameas the non-conducting sphere once you are outside the sphere. If you need clarification or how to find these equations, letme know. Hope this helps

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