A parallel-plate capacitor is made by placing polyethylene ( =2.3) between two sheets of aluminum foil. The area of eachsheet of aluminum foil is 410 cm2, and the thickness ofthe polyethylene is 0.5 mm. The permittivity of free space is8.85 × 1012 C2/N · m2. Find thecapacitance. Answer in units of nF. A parallel-plate capacitor is made by placing polyethylene ( =2.3) between two sheets of aluminum foil. The area of eachsheet of aluminum foil is 410 cm2, and the thickness ofthe polyethylene is 0.5 mm. The permittivity of free space is8.85 × 1012 C2/N · m2. Find thecapacitance. Answer in units of nF.
Explanation / Answer
Area of a parallel platecapacitor is A = 410 cm2 = 410*10-4 m2 seperated by a distance d = 0.5 mm = 0.5*10-3 m dielectric constant k = 2.3 Capacitance of a Capacitor is C = k 0A / d = 2. 3* 8.85*10-12 C2 /N m2 * 410 *10-4 m2 / 0.5 *10-3m = 1669 nF