12.) Two capacitors, C 1 = 4.00 µF and C 2 =15.0 µF, are connected in parallelan

Question

12.) Two capacitors, C1 = 4.00 µF and C2 =15.0 µF, are connected in paralleland the resulting combination is connected to a 9.00 V battery. (a) What is the equivalent capacitance of thecombination?
____________ µF

(b) What is the potential difference across each capacitor?
C1 = ____________ V
C2 = ____________ V

(c) What is the charge stored on each capacitor?
C1 = _____________ µC
C2 = _____________ µC (a) What is the equivalent capacitance of thecombination?
____________ µF

(b) What is the potential difference across each capacitor?
C1 = ____________ V
C2 = ____________ V

(c) What is the charge stored on each capacitor?
C1 = _____________ µC
C2 = _____________ µC

Explanation / Answer

Given :   C1 = 4.00 µF and C2 =15.0 µF V = 9.0 V       Capacitors inparallel     a ) Ceq = C1 + C2             = 4 + 15              = 19 F     C = q / V    q = Ceq V       = ( 19 F ) ( 9 V )       = 171 C      V1 = q / C1 = -------- v      V2 = q / C2 = ----------v c ) As we know that    charge stored in acapacitor C = q /V     q1 = C1 V1 = ----- C     q2 = C2 V2 = ----- C    Plugin the values and solve it

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