Oppositely charged parallel plates are separated by5.35 mm. A potential differen
ID: 1666266 • Letter: O
Question
Oppositely charged parallel plates are separated by5.35 mm. A potential difference of 600 Vexists between the plates. (a) What is the magnitude of the electric field between theplates?(b) What is the magnitude of the force on an electron between theplates?
2 N
(c) How much work must be done on the electron to move it to thenegative plate if it is initially positioned 2.86 mm from the positive plate?
3 J Oppositely charged parallel plates are separated by5.35 mm. A potential difference of 600 Vexists between the plates. (a) What is the magnitude of the electric field between theplates?
(b) What is the magnitude of the force on an electron between theplates?
2 N
(c) How much work must be done on the electron to move it to thenegative plate if it is initially positioned 2.86 mm from the positive plate?
3 J
Explanation / Answer
d = 5.35 mm. V = 600 V a) E = V/d = 1.12*105 V/m b) F = eE = 1.79*10-14 N c) W = F*(5.35 - 2.86)*10-3 = 4.47*10-17J