A point charge q = 5.20×10 -6 C isplaced at one corner of a cube of edge a = 0.3

Question

A point charge q = 5.20×10-6C isplaced at one corner of a cube of edge a = 0.38 m. What isthe flux through each of the cube faces? See the figure. (Hint: UseGauss' law and symmetry arguments.)
What is theflux through side A? (A). 0.00 N*m^2/C Whatis the flux through side B? (B). ? A point charge q = 5.20×10-6C isplaced at one corner of a cube of edge a = 0.38 m. What isthe flux through each of the cube faces? See the figure. (Hint: UseGauss' law and symmetry arguments.)
What is theflux through side A? (A). 0.00 N*m^2/C Whatis the flux through side B? (B). ?

Explanation / Answer

Given :     Charge ( q ) = 5.2 * 10-6C a = 0.38 m (a)    if we stack identical cubes side byside and directly on top of each other we will find that eightcubes will meet at any    corner thus one-eigth of the field linesemanating from the point charge pass through a cube with a cornerat the charge    and the total flux through the surface ofsuch a cube is q / 8 o    now the field lines are radial so at each ofthe three cube faces that meet at the charge the lines are parallelto the face and    the flux through the face is zero (b)    the fluxes through each of the other threefaces are the same so the flux through each of them is one-third ofthe total, the    flux through each of these faces is (1 / 3)(q / 8 o) total flux = charge encl / = 5.2 x 10-6 / 8.85 x 10-12 =--------

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