A 1.04 µF capacitor isconnected in series with a 2.10 µFcapacitor. The 1.04 µF c

Question

A 1.04 µF capacitor isconnected in series with a 2.10 µFcapacitor. The 1.04 µF capacitor carries a charge of+9.6 µC onone plate, which is at a potential of 50.5V. (a) Find the potential on the negative plate of the 1.04µF capacitor.
(b) Find the equivalent capacitance of the two capacitors. A 1.04 µF capacitor isconnected in series with a 2.10 µFcapacitor. The 1.04 µF capacitor carries a charge of+9.6 µC onone plate, which is at a potential of 50.5V. (a) Find the potential on the negative plate of the 1.04µF capacitor.
(b) Find the equivalent capacitance of the two capacitors.

Explanation / Answer

potential across 1.04cap is   V = Q /C = 9.6 / 1.04 =   9.23 volts . potential of neg side = 50.5 -9.23 =    41.27 volts . total capacitance = 1.04 * 2.10 / (1.04 +2.10) =    0.6955uF

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