Two capacitors, C 1 = 20 µF and C 2 =4.0 µF, are connected inparallel and charge

Question

Two capacitors, C1 = 20 µF and C2 =4.0 µF, are connected inparallel and charged with a 100 Vpower supply. (a) Calculate the total energy stored in twocapacitors.
1 J
(b) What potential difference would be required across the same twocapacitors connected in series in order that the combination storethe same energy as in (a)?
2 V
(a) Calculate the total energy stored in twocapacitors.
1 J
(b) What potential difference would be required across the same twocapacitors connected in series in order that the combination storethe same energy as in (a)?
2 V

Explanation / Answer

Given    C1 = 20 F =20*10-6 F    C2 = 4 F   =4*10-6 F C1 and C2 are connected inparallel       So ,   equivalentcapacitance   Cp   =C1 + C2                                                              = 24*10-6 F        Total energy stored inthe capacitors                       U = ( 1/2) Cp V2                          = 0.5 *  24*10-6 F *100*100                          = 0.12 J      C1 and C2are connected in series       So ,  equivalent capacitance   Cs   =C1   C2 / C1 + C2                                                           = 20*4 /24                                                             = 3.33 F       capacitors are in seriescombination   charge on each capacitor   issame                   Q = Cs V                         = 3.33 *100                         = 3.33 mC        potential on eachcapacitor                   V1 = Q / C1                  V2   = Q / C2                                                               

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