Two pointparticles ofcharge Q 1 = 46 µCand Q 2 = 86 µC are found to have a poten

Question

Two pointparticles ofcharge Q1 = 46 µCand Q2 = 86 µC are found to have a potentialenergy of 42 J. What is thedistance between the charges?
m
Two pointparticles ofcharge Q1 = 46 µCand Q2 = 86 µC are found to have a potentialenergy of 42 J. What is thedistance between the charges?
m
Two pointparticles ofcharge Q1 = 46 µCand Q2 = 86 µC are found to have a potentialenergy of 42 J. What is thedistance between the charges?
m
Two pointparticles ofcharge Q1 = 46 µCand Q2 = 86 µC are found to have a potentialenergy of 42 J. What is thedistance between the charges?
m

Explanation / Answer

Given
  Q1 = 46 µC    Q2 = 86 µC    V =    42 J.      we know that             V = k Q 1 Q2 / r    where   r is the distancebetween two point charges             V = (9*109 )(46C )(86C)   /r               r    = 9*109 )(46C)(86C)     / 42                    = 0.847 m

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