The power P delivered to each resistor is the product ofthe current squared ( I
ID: 1667589 • Letter: T
Question
The power P delivered to each resistor is the product ofthe current squared (I2) and the correspondingresistance R, or P = I2R. Theresistances are known, and Ohm's law can be used to find thecurrent. Ohm's law states that the current in the circuit (which isalso the current through each of the resistors) equals the voltageV of the battery divided by the equivalent resistanceRs of the two resistors: I =V/Rs. Since the resistors are connected in series,we can obtain the equivalent resistance by adding theresistances.Three resistors, 1.5 ,3.5 , and 6.5 , are connected in series across a40-V battery. Find the power deliveredto each resistor.
1.5 resistor 1_________ W 3.5 resistor 2__________W 6.5 resistor 3__________W 1.5 resistor 1_________ W 3.5 resistor 2__________W 6.5 resistor 3__________W
Explanation / Answer
the total resistance : R=R1+R2+R3=1,5+3,5+6,5=11,5 => the current: I=U/R=40/11,5 = 3,48 A the power in each resistor: P1= I^2.R1 =18,166 W P2=I^2.R2=43,386 W P3=I^2.R3=78,818 W