One strategy in a snowball fight is to throw a snowball at a highangle over leve

Question

One strategy in a snowball fight is to throw a snowball at a highangle over level ground. While your opponent is watching thatsnowball, you throw a second one at a low angle timed to arrivebefore or at the same time as the first one. Assume that bothsnowballs are thrown with a speed of 35.0 m/s. The first one is thrown at an angle of65.0°with respect to the horizontal. (a) At what angle should the second snowball bethrown to arrive at the same point as the first?
1°

(b) How many seconds later should the second snowball be thrownafter the first in order for both to arrive at the same time?
2 s (a) At what angle should the second snowball bethrown to arrive at the same point as the first?
1°

(b) How many seconds later should the second snowball be thrownafter the first in order for both to arrive at the same time?
2 s

Explanation / Answer

First, the angle that it should be thrown at will be 25degrees. 65 and 25 are complimentary angles and their sin andcos components will switch. For the second, you can find out how long the first snowballwill be in the air vy = voy +gt where voy= sin 65 * 35m/s = 31.72m/s t = -31.72 -31.72/9.8m/s2 = 6.47s For the second voy = sin 25 * 35m/s = 14.79 t = -14.79 - 14.79/9.8m/s2 = 3.02s 6.47s - 3.02s = 3.45s later Hope that helps

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