A 2800 kg truck traveling north at42 km/h turns east and accelerates to59 km/h.

Question

A 2800 kg truck traveling north at42 km/h turns east and accelerates to59 km/h. (a) What is the change in the truck's kineticenergy?


(b) What is the magnitude of the change in the linear momentum ofthe truck?


(c) What is the direction of the change in the linear momentum ofthe truck?
(measured clockwise from east) (a) What is the change in the truck's kineticenergy?


(b) What is the magnitude of the change in the linear momentum ofthe truck?


(c) What is the direction of the change in the linear momentum ofthe truck?
(measured clockwise from east)

Explanation / Answer

Mass m = 2800 kg

Initial velocity u = 42 km/ h = 42 * ( 5/ 18 ) m / s=11.666 m / s

                          u= 11.6666 j   m / s

Final velocity v = 59 km / h = 59 * ( 5/ 18 ) m / s=16.3888 m / s

                       v = 16.3888 i     m / s

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