For the followingproblem choose the best answer and EXPLAIN why you chose theanswer. Two parallel conducting plates, separated by a distance d, are connected to a battery of emf E. Which of the following is correct if the plate separation is doubled while the battery remains connected? The electric charge on the plates is doubled. The electric charge on the plates is halved. The potential difference between the plates is doubled. The potential difference between the plates is halved. The capacitance is unchanged.
Explanation / Answer
The battery remain unchanged so the potential difference isalso unchanged. distance is double so the capacitance is changed (sinceC=0*S/d). The electric field E=U/d so if d is double then E ishalve. we also have E=Q/s0. so if E is halve then Q ishalve.