A capacitor consists of two charged disks of radius 3 mseperated by a distance s

Question

A capacitor consists of two charged disks of radius 3 mseperated by a distance s = 2 mm (see the figure). Themagnitude of the charge on each disk is 33 C. Considerpoints A, B, C, and D insisde the capacitor, as shown in thediagram. The distance s1 = 1.7 mm, and the distance s2= 0.7mm. Please provide answers with the units asked for eachpart. Thank you. (a) What is the electric field inside the capacitor? E=< ________ , ________ , ________ > N/C What is l along this path? l = < ________ ,________ , ________ > m What is l along this path? l = < ________ ,________ , ________ > m What is l along this path? l = < ________, ________ , ________ > m
A capacitor consists of two charged disks of radius 3 mseperated by a distance s = 2 mm (see the figure). Themagnitude of the charge on each disk is 33 mu C. Considerpoints A, B, C, and D insisde the capacitor, as shown in thediagram. The distance s1 = 1.7 mm, and the distance s2= 0.7mm. = 8.85e-12 Please provide answers with the units asked for eachpart. Thank you. (a) What is the electric field inside the capacitor? E= N/C (b) First, calculate the potential difference What is DELTA l along this path? DELTA l = m What is ___________ volts. (c) Next, calculate the potential difference . What is DELTA l along this path? DELTA l = m What is ________ volts. (d) Finally, calculate the potential difference . What is DELTA l along this path? DELTA l = m What is ________ volts.

Explanation / Answer

I will assume the x direction is to the right and the ydirection is upward. Then we have... . (a)   E field inside is only in the xdirection and is equal to .         E = q / A = 33 x 10-6 / 8.85 x10-12 * 3.002  =    131879 N/C . So the answer is       E = (131879   ,     0    ,    0  )    N/C . (b) going from A to B ,  L is    ( -0.0017 ,   0   ,    0  )   m .    so     VB - VA   =    - 131879* -0.002 =      224Volts . (c) going from B to C ,  L is    (  0 ,   -0.0007   ,    0  )   m .    so     VC - VB  =    - 131879 * 0  =      0 Volts . (d) going from Cto A ,   L is   (  0.0017 ,    0.0007 ,   0   )   m .    so    VA - VC =    - 131879 *  0.0017  +     0 * 0.0007   =      -224Volts .    so     VC - VB  =    - 131879 * 0  =      0 Volts . (d) going from Cto A ,   L is   (  0.0017 ,    0.0007 ,   0   )   m .    so    VA - VC =    - 131879 *  0.0017  +     0 * 0.0007   =      -224Volts .    so    VA - VC =    - 131879 *  0.0017  +     0 * 0.0007   =      -224Volts

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