Not too sure on how to do this problem.... A circular surface with a radius of 0

Question

Not too sure on how to do this problem....

A circular surface with a radius of 0.057 m is exposed to a uniformexternal electric field of magnitude 1.44 × 104N/C. The electric flux through the surface is 78 N ·m2/C. What is the angle between the direction of theelectric field and the normal to the surface? Not too sure on how to do this problem....

A circular surface with a radius of 0.057 m is exposed to a uniformexternal electric field of magnitude 1.44 × 104N/C. The electric flux through the surface is 78 N ·m2/C. What is the angle between the direction of theelectric field and the normal to the surface?

Explanation / Answer

A circular surface of radius r = 0.057m          Area A = r2                        = ( 0.057 m )2                         =1.02*10-2 m2 Electric flux = 78 N m2 /C      Electric field E =1.44*104 N / C          = E A cos         cos = 78 Nm2 / C /  1.44*104 N /C *1.02*10-2 m2                  = 57.90

Related Questions

Navigate

• Browse (All)
• Browse N
• Subjects

---