Two capacitors, one 12.0 f and the other of unknowncapacitance, are connected in

Question

Two capacitors, one 12.0 f and the other of unknowncapacitance, are connected in paralel across a battery of EMF 9.0V. The total energy stored in the two capacitors is 0.0115 J. (A) What is the unknown capacitance, C? (B) What is the total charge stored on the twocapacitors? Any help is greatly appreciated Two capacitors, one 12.0 f and the other of unknowncapacitance, are connected in paralel across a battery of EMF 9.0V. The total energy stored in the two capacitors is 0.0115 J. (A) What is the unknown capacitance, C? (B) What is the total charge stored on the twocapacitors? Any help is greatly appreciated

Explanation / Answer

Given that        C1 = 12 F        V = 9.0 V        U = 0.0115 j We know that                U = 0.5 Ceq V2            ==>Ceq = 2 U / V2                          = 2 * 0.0115 / 81                           = 283 F So that capacitance of unknown capacitor is C2 = Ceq- C1 = 283F - 12F = 271 F Total charge Q = C V = 283F * 9 = 2.547 mC

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