( a ) Find theangular speed about the polar axis, as well as the translationalsp

Question

(a) Find theangular speed about the polar axis, as well as the translationalspeed and acceleration of a point on the earth’s surface at alatitude of 45°N.

(b) How do these values compare with the correspondingvalues for a point on the equator? (The radius of the earth is6.38 ×106 m.) (a) Find theangular speed about the polar axis, as well as the translationalspeed and acceleration of a point on the earth’s surface at alatitude of 45°N.

(b) How do these values compare with the correspondingvalues for a point on the equator? (The radius of the earth is6.38 ×106 m.)

Explanation / Answer

(a) angular speed = 1 revolution / 24hours = 6.2832 radians / 86400 seconds = .          =    7.272 x10-5 rad/sec .      translational speed = r = Rcos = 7.272 x10-5 * 6.38 x 106 * cos45 =   328 m/s .          acc = * trans speed =       0.0239 m/s2 . (b)   atequator       .      translational speed = r = Rcos = 7.272 x10-5 * 6.38 x 106 * cos0 =   464 m/s .          acc = * trans speed =      0.0337 m/s2 . (b)   atequator       .      translational speed = r = Rcos = 7.272 x10-5 * 6.38 x 106 * cos0 =   464 m/s .          acc = * trans speed =      0.0337 m/s2      translational speed = r = Rcos = 7.272 x10-5 * 6.38 x 106 * cos0 =   464 m/s .          acc = * trans speed =      0.0337 m/s2

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