A 2000 kg truck traveling north at 41 km/h turns east andaccelerates to 57 kn/h.

Question

A 2000 kg truck traveling north at 41 km/h turns east andaccelerates to 57 kn/h. What is the change in thetruck’s kinetic energy? What is the magnitude of the changein the linear momentum of the truck (kg m/s)? What is the directionof the change in the linear momentum of the truck (measuredclockwise from east)?

Please provide me with the formulas and steps so I know how youcame to the final answers. A 2000 kg truck traveling north at 41 km/h turns east andaccelerates to 57 kn/h. What is the change in thetruck’s kinetic energy? What is the magnitude of the changein the linear momentum of the truck (kg m/s)? What is the directionof the change in the linear momentum of the truck (measuredclockwise from east)?

Please provide me with the formulas and steps so I know how youcame to the final answers.

Explanation / Answer

given that mass = m = 2000kg finnal spee = vf= 57km/h = 57 *103m/3600s = 15.83m/s intial speed = vi= 41km/hr =13.05m/s change in kinetic energy is                                             K = 1/2*mvf2- 1/2 *mvi2 plug in values = ------J the magnitude of change in velocity v=(-vi)2 + (vf)2                                                     = ---------km/h magnitude of change in momentum = p = mv                                                   = ----------kgm/s the angle sout of east is =tan-1 (vi/vf) =--------0                                                     = ---------km/h magnitude of change in momentum = p = mv                                                   = ----------kgm/s the angle sout of east is =tan-1 (vi/vf) =--------0   

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