A 95 turn square wire coil ofarea 0.040 m 2 rotates about a vertical axis at1730

Question

A 95 turn square wire coil ofarea 0.040 m2 rotates about a vertical axis at1730 rev/min, as indicated in FigureP20.30. The horizontal component of the Earth's magnetic field atthe location of the loop is 2.0 X 10-5 T. Calculate themaximum emf induced in the coil by the Earth's field.
1 V http://s1002.photobucket.com/albums/af149/jakeloftin2186/?action=view&current=5.jpg&newest=1 A 95 turn square wire coil ofarea 0.040 m2 rotates about a vertical axis at1730 rev/min, as indicated in FigureP20.30. The horizontal component of the Earth's magnetic field atthe location of the loop is 2.0 X 10-5 T. Calculate themaximum emf induced in the coil by the Earth's field.
1 V http://s1002.photobucket.com/albums/af149/jakeloftin2186/?action=view&current=5.jpg&newest=1

Explanation / Answer

   Angularspeed      =   1730   rev/min                                  =   1730* 2 / 60      rad/s                                  =   181.07   rad/s    No. ofturns   N   =   95    area ofcoil   A   =   0.040   m2    Magnetic fieldstrength   B   =   2.0* 10-5   T    Maximum inducedEMF      Emax   =   * N * B * A                                                          =   181.07* 95 * 2.0 * 10-5 * 0.040                                                          =   1.376* 10-2   V    Magnetic fieldstrength   B   =   2.0* 10-5   T    Maximum inducedEMF      Emax   =   * N * B * A                                                          =   181.07* 95 * 2.0 * 10-5 * 0.040                                                          =   1.376* 10-2   V

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