A resistor with R = 3.0k is connected to an AC generator that operates at 60 Hzw
ID: 1674665 • Letter: A
Question
A resistor with R = 3.0k is connected to an AC generator that operates at 60 Hzwith an amplitude of 37 V. (a) Find the amplitude of the current throughthe resistor.1 A
(b) Find the maximum instantaneous power dissipated in theresistor.
2 W
(c) Find the minimum instantaneous power dissipated in theresistor.
3 W
(d) Find the average power dissipated in the resistor.
4 W
(e) How long will it take this resistor to dissipate 190 J?
5 s
(a) Find the amplitude of the current throughthe resistor.
1 A
(b) Find the maximum instantaneous power dissipated in theresistor.
2 W
(c) Find the minimum instantaneous power dissipated in theresistor.
3 W
(d) Find the average power dissipated in the resistor.
4 W
(e) How long will it take this resistor to dissipate 190 J?
5 s
Explanation / Answer
(a) Find the amplitude of the current throughthe resistor.I= V/R I= 37/3.0x103 =0.0123 A
(b) Find the maximum instantaneous power dissipated in theresistor.
P=IV P=0.456 W
(c) Find the minimum instantaneous power dissipated in theresistor.
P= 0 W at V(t)=0 I(t) =0 therefore P(t)=0
(d) Find the average power dissipated in the resistor.
P=Vrms2/R P= (2/2 37)2 /3.0x103 P= 0.0087 W
(e) How long will it take this resistor to dissipate 190 J?
Since P=Energy/time Energy = 190 / 0.0087 = 21,786 s