The output voltage of an AC generator is given by v = 480 V sin (60 t ). The gen

Question

The output voltage of an AC generator is given by v= 480 V sin (60t). The generator is connectedacross a 0.800 H inductor. Find thefollowing. (a) frequency of the generator
1 Hz

(b) rms voltage across the inductor
2 V

(c) inductive reactance
3

(d) rms current in the inductor
4 A

(e) maximum current in the inductor
5 A

(f) average power delivered to the inductor
______________________ W
Your response differs from the correct answerby orders of magnitude.
(g) Find an expression for the instantaneouscurrent. (Use the following variables as necessary: t, pi.)
_________________________________

(h) At what time after t = 0 does the instantaneouscurrent first reach 1.00 A? (Use the inverse sinefunction.)
____________________ s
Your response differs from the correct answerby orders of magnitude. (a) frequency of the generator
1 Hz

(b) rms voltage across the inductor
2 V

(c) inductive reactance
3

(d) rms current in the inductor
4 A

(e) maximum current in the inductor
5 A

(f) average power delivered to the inductor
______________________ W
Your response differs from the correct answerby orders of magnitude.
(g) Find an expression for the instantaneouscurrent. (Use the following variables as necessary: t, pi.)
_________________________________

(h) At what time after t = 0 does the instantaneouscurrent first reach 1.00 A? (Use the inverse sinefunction.)
____________________ s
Your response differs from the correct answerby orders of magnitude.

Explanation / Answer

Part g: I = Im*sin(60t-/2) I = 3.18sin(60t-/2) Part h: Put I = 1 A in the above equation 1=3.18*sin(60t-/2) sin(60t-/2) = 1/3.18 = 0.31447 60t-/2 = Inverse sin of ( 0.31447) =0.32 60t = 0.32+/2 = 1.891 t = 1.891/60 = 0.01003 s Part f: Average power over a cycle is 0 in an inductive circuit. However the maximum instataneous power = Vrms * Irms =339.4*2.252 = 764.33 W

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