Hi, I need help with the following question. Could you pleaseshow your work so t

Question

Hi, I need help with the following question. Could you pleaseshow your work so that I may better understand the question?Thanks!

1. A radioactive Phosphorus nucleus with Atomic number 15 and massnumber 32,
beta decays by emitting an Electron and an Antineutrino. (The aboveisotope of
Phosphorus has a mass of m=31.973u)
a. What is the atomic number and mass number of the daughternucleus?

b. What element is the daughter nucleus?

c. What is the rest Energy of the Phosphorus nucleus in eV? (1 u =931.5 MeV)

d. If the maximum energy of the emitted Electron is 1.7MeV, what istheatomic mass of the daughter nucleus in atomic mass units u?Assume thatthe antineutrino has negligible kinetic energy and mass.The daughter nucleus has zero speed after the decay.

Explanation / Answer

15P32 becomes16S32   because the charge of the nucleus increases by 1 The daughter is Silicon with mass 32 1 Mev = 1 * 10E6 eV 31.973 u * 931.5 Mev / u * 106 eV / MeV = 2.978 *10E10 eV    the rest energy of the Phosphorus The rest energy of the P nucleus is also 2.978 * 10E4MeV The rest energy of the electron is .511 MeV The the rest energy of the daughter nucleus is (29780 - .511 - 1.7) Mev = 29870 Mev to the significantfigures given in the problem

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