A screen is placed 1.10 m behind a single slit. Thecentral maximum in the resulting diffraction pattern on the screenis 1.80 cm wide-that is, the two first-order diffractionminima are separated by 1.80 cm. What is the distance between the two second-orderminima? y2 =______ cm A screen is placed 1.10 m behind a single slit. Thecentral maximum in the resulting diffraction pattern on the screenis 1.80 cm wide-that is, the two first-order diffractionminima are separated by 1.80 cm. What is the distance between the two second-orderminima? y2 =______ cm
Explanation / Answer
we have condition for diffraction minima sin=k*/b k=1 centre maxima 1.8cm =/b*L L=1.1 m k=2 => x=2/b*L= 3.6 cm