A discus thrower accelerates a discus from rest to a speed of25.7 m/s by whirlin

Question

A discus thrower accelerates a discus from rest to a speed of25.7 m/s by whirling it through1.20 rev. Assume the discus moves onthe arc of a circle 1.04 m inradius. (a) Calculate the final angular speed of thediscus.
1 rad/s

(b) Determine the magnitude of the angular acceleration of thediscus, assuming it to be constant.
2 rad/s2

(c) Calculate the time interval required for the discus toaccelerate from rest to 25.7 m/s.
3 s A discus thrower accelerates a discus from rest to a speed of25.7 m/s by whirling it through1.20 rev. Assume the discus moves onthe arc of a circle 1.04 m inradius. (a) Calculate the final angular speed of thediscus.
1 rad/s

(b) Determine the magnitude of the angular acceleration of thediscus, assuming it to be constant.
2 rad/s2

(c) Calculate the time interval required for the discus toaccelerate from rest to 25.7 m/s.
3 s (a) Calculate the final angular speed of thediscus.
1 rad/s

(b) Determine the magnitude of the angular acceleration of thediscus, assuming it to be constant.
2 rad/s2

(c) Calculate the time interval required for the discus toaccelerate from rest to 25.7 m/s.
3 s

Explanation / Answer

(a)   angular speed = v / r = 25.7 /1.04 =    24.71 rad/s . (b)   final speed2   = 2* acc * distance       where distance = 1.20 rev   = 7.54 rad .         24.712   = 2 * acc * 7.54 . acc =   40.5rad/s2 . (c)   time = final speed / acc=   24.71 / 40.5 =    0.610seconds . (c)   time = final speed / acc=   24.71 / 40.5 =    0.610seconds

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