(a) What is the magnitude of the magnetic field createdby I 1 at the locationof

Question

(a) What is the magnitude of the magnetic field createdby I1 at the locationof I2?
T  ---Direction---out of the monitorin the -x directioninto the monitorin the +x directionin the +y directionin the -y direction

(b) What is the force per unit length exertedon I2 by I1?
N/m  ---Direction---in the +x directionout of the monitorin the -y directioninto the monitorin the +y directionin the -x direction

(c) What is the magnitude of the magnetic field createdby I2 at the locationof I1?
T  ---Direction---in the -y directioninto the monitorin the +y directionout of the monitorin the -x directionin the +x direction

(d) What is the force per length exertedby I2 on I1?

N/m   ---Direction---into the monitorout of the monitorin the -x directionin the +x directionin the -y directionin the +y direction
Two long, parallel conductors, separated by 14.0 cm, carry currents in the same direction.The first wire carriescurrent I1 = 2.00 A, and the secondcarries I2 = 8.00 A (See figurebelow. Assume the conductors lie in the plane of the page.) (a) What is the magnitude of the magnetic field createdby I1 at the locationof I2? T (b) What is the force per unit length exertedon I2 by I1? N/m (c) What is the magnitude of the magnetic field createdby I2 at the locationof I1? 228.57 T (d) What is the force per length exertedby I2 on I1? N/m

Explanation / Answer

(a)B=0I/2d=2*10-7*(2)/(0.14)=______T (out of the monitor) (b) (F/L )= (0I1I2)/(2d) =2*10-7*(2)(8)/ (0.14) = _____ N/m( - y-direction) (c)B=0I/2d=2*10-7*(8)/(0.14)= ____ T( into the monitor) (d) (F/L )= (0I1I2)/(2d) =2*10-7*(2)(8)/ (0.14) = ______ N/m( + y-direction)

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