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Two electrons in the same atom have n = 3 and = 2. (a) How many quantum numbers

ID: 1677089 • Letter: T

Question

Two electrons in the same atom have n = 3 and = 2. (a) How many quantum numbers are there for thepossible states of the atom?
1
Your response differs from the correct answerby 10% to 100%.

(b) How many states would be possible if the exclusion principledid not apply to the atom?
2
Your response differs from the correct answerby 10% to 100%. (a) How many quantum numbers are there for thepossible states of the atom?
1
Your response differs from the correct answerby 10% to 100%.

(b) How many states would be possible if the exclusion principledid not apply to the atom?
2
Your response differs from the correct answerby 10% to 100%.

Explanation / Answer

Quantum numbers for n=3 electron: n = 3 l = 0, 1, 2 (3 options) m = -2, -1, 0, 1, 2 (5 options) spin = 1/2, -1/2 (2 options) To find the number of combinations, choosing one number fromeach row, multiply all the options together. The n=3 electron has (3*5*2 = 30) combinations. ... The same calculations go for the n=2 atom. n = 2 l = 0, 1 (2 options) m = -1, 0, 1 (3 options) spin = 1/2, -1/2 (2 options) 2*3*2 = 12 The n=2 electron has 12 combinations. ... Multiplying these two number of combinations together givesthe total number of possible quantum states for this atom. ... This atom has 360 combinations of quantumnumbers.