(a) What is the capacitance of the system? 1 pF (b) If the charges are changed t

Question

(a) What is the capacitance of the system?
1 pF

(b) If the charges are changed to +186 pC and -186 pC, what does thecapacitance become?
2 pF

(c) What does the potential difference become?
3 V Explination Please The two metal objects in the figure have net charges of+65 pC and-65 pC, whichresult in a 12 V potential differencebetween them. (a) What is the capacitance of the system? 1 pF (b) If the charges are changed to +186 pC and -186 pC, what does thecapacitance become? 2 pF (c) What does the potential difference become? 3 V Explination Please

Explanation / Answer

charge on two metal objects   q =65 pC potential difference between them   V = 12 V     Capacitance of thesystem                   C = Q / V                      = 65*10-12    / 12                       =   5.41 pF     charges are changed to  186   p C         capacitance of thesystem is              C =    186 / 12   = 15.5 pC       poential difference  V = 12 V

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