9) A converging lens has a focal length of 19.3 cm. Give the image distance and

Question

9) A converging lens has a focal length of 19.3 cm. Give the image distance and magnification forthe following object distances, using the correct sign conventions.Select all options that correctly describe the image. If the imageis located at infinity, enter "infinity" for the image distance andfor the magnification, and select "no image is formed". (a) object distance = 10.7cm
image distance cm
magnification
X
side of lens opposite the objectvirtual sameside of lens as the object real no imageis formed upright inverted 9) A converging lens has a focal length of 19.3 cm. Give the image distance and magnification forthe following object distances, using the correct sign conventions.Select all options that correctly describe the image. If the imageis located at infinity, enter "infinity" for the image distance andfor the magnification, and select "no image is formed". (a) object distance = 10.7cm
image distance cm
magnification
X
side of lens opposite the objectvirtual sameside of lens as the object real no imageis formed upright inverted side of lens opposite the objectvirtual sameside of lens as the object real no imageis formed upright inverted side of lens opposite the objectvirtual sameside of lens as the object real no imageis formed upright inverted

Explanation / Answer

Given focal length of the cnverging lens f = 19.3 cm object distance   do  = 10.7 cm Thin lens equation is             1 / do + 1 / d i   = 1 /f            1 /  10.7 + 1 /di    = 1 / 19.3                    1 / d i    = 1 /19.3   - 1 /10.7 cm      image distance   d i   = -24cm   the image is formed same side to theobject      So the image   is virtual image   Magnification   M = - di   / d o                                 =   -  ( - 24 ) / 39.2   =2.24 the image   is  uprighted withrespective to the object

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