Chapter 4: #88: James S Walker, 4th ed A mountain climber jumps a crevasse by le

Question

Chapter 4: #88: James S Walker, 4th ed
A mountain climber jumps a crevasse by leaping horizontal withspeed Vo. If the climbers direction of motion of landing is belowthe horizontal, what is the height difference h between the twosides of the crevasse.

I'm completely stuck on this question. I look at theanswer:
I algebraically understand everything up to the part wherethey say:
vsin/vcos = gt/vo
I don't understand how you get to this point.


But on another note, I was wondering how to tackle thisproblem.
Thanks,



A mountain climber jumps a crevasse by leaping horizontal withspeed Vo. If the climbers direction of motion of landing is belowthe horizontal, what is the height difference h between the twosides of the crevasse.

I'm completely stuck on this question. I look at theanswer:
I algebraically understand everything up to the part wherethey say:
vsin/vcos = gt/vo
I don't understand how you get to this point.


But on another note, I was wondering how to tackle thisproblem.
Thanks,

Explanation / Answer

Ans.   if the velocity be v making an angle with horizontal,             then horizontal component velocity=vcos &                    vertical component velocity=vsin          Now givenvcos=v0         from v=u+ft                0=vsin-gt                vsin=gt             (vsin)/(vcos)=gt/v0   [proved]         for the givenproblem,           from the above relation u can get t & then putting this t inthe following relation u can get h value.               s=ut+0.5ft2               h=vsin*t-0.5*g*t2      alternatively, u can use thefollowing relation,                v2=u2+2fs                02=(vsin)^2-2*g*h             h=(vsin)^2/(2*g)              alternatively, u can use thefollowing relation,                v2=u2+2fs                02=(vsin)^2-2*g*h             h=(vsin)^2/(2*g)        

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