A 1.0-kg copper block is given aninitial speed of 6.0 m/s ona rough horizontal s

Question

A 1.0-kg copper block is given aninitial speed of 6.0 m/s ona rough horizontal surface. Because of friction, the block finallycomes to rest. (a) If the block absorbs 85% of its initial kinetic energy asinternal energy, calculate its increase in temperature.
°C

(b) What happens to the remaining energy? Itvanishes from the universe.Itis absorbed by the horizontal surface on which the blockslides.    Itbecomes chemical energy.Itis so minute that it doesn't factor into theequation. (a) If the block absorbs 85% of its initial kinetic energy asinternal energy, calculate its increase in temperature.
°C

(b) What happens to the remaining energy? Itvanishes from the universe.Itis absorbed by the horizontal surface on which the blockslides.    Itbecomes chemical energy.Itis so minute that it doesn't factor into theequation. Itvanishes from the universe.Itis absorbed by the horizontal surface on which the blockslides.    Itbecomes chemical energy.Itis so minute that it doesn't factor into theequation. Itvanishes from the universe.Itis absorbed by the horizontal surface on which the blockslides.    Itbecomes chemical energy.Itis so minute that it doesn't factor into theequation.

Explanation / Answer

Q = .85 * 1/2 m v2 = .85 * 1/2 * 36 = 15.3 J = 15.3J / (4.19 J/cal) = 3.65 cal This is the heat absorbed by the block Q = m sCu T T = 3.65 / (1000 * .093) = .039 deg C The rest of the heat would be lost to the surroundings, mainlythe horizontal surface.

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