A jogger maintains a speed of 2.5 m/s for 216 m until heencounters a stoplight, and he abruptly stops and waits 28s for thelight to change. He then resumes his excercise and maintains aspeed of 3.4 m/s for the remaining 52 m to his home.What is theaverage velocity for this entire interval? I am not sure which equation to use or what goes where in theequation. I used X-Xo= Vot +1/2at2 But when I entered in my final answer it said myanswer was wrong. So I'm not sure if I'm even on the right track atall. A jogger maintains a speed of 2.5 m/s for 216 m until heencounters a stoplight, and he abruptly stops and waits 28s for thelight to change. He then resumes his excercise and maintains aspeed of 3.4 m/s for the remaining 52 m to his home.What is theaverage velocity for this entire interval? I am not sure which equation to use or what goes where in theequation. I used X-Xo= Vot +1/2at2 But when I entered in my final answer it said myanswer was wrong. So I'm not sure if I'm even on the right track atall.
Explanation / Answer
Totaldistance d = 216 + 52 = 268 m totaltime t = 216/2.5 + 28 + 52/3.4 = 129.69 s averagevelocity vavg = d/ t = 268 / 129.69 = 2.066 m/s