uggg, our teacher never went over this and assigns this forhomework. When a 2.60

Question

uggg, our teacher never went over this and assigns this forhomework. When a 2.60-kg object is hungvertically on a certain light spring described by Hooke's law, thespring stretches 2.44 cm. (a) What is the force constant of the spring?____ N/m

(b) If the 2.60-kg object isremoved, how far will the spring stretch if a 1.30-kg block is hung on it?
_____ cm

(c) How much work must an external agent do to stretch the samespring 6.60 cm from itsunstretched position? ______ J uggg, our teacher never went over this and assigns this forhomework. (a) What is the force constant of the spring?____ N/m

(b) If the 2.60-kg object isremoved, how far will the spring stretch if a 1.30-kg block is hung on it?
_____ cm

(c) How much work must an external agent do to stretch the samespring 6.60 cm from itsunstretched position? ______ J

Explanation / Answer

Given    mass of the object = 2.60kg                                    x = 2.44cm = 2.44*10-2m          (a) Force constant of the spring k =F/x N/m                                                         =2.6*9.8/2.44*10-2 =1044N/m     (b)Here m =1.30kg                x =F/k =1.3*9.8/1044 =.01m      (c)Given x = 6.6cm=6.6*10-2m                Workdone= 1/2 k x2  =0.5*1044*(6.6*10-2)2 =2.27J

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