11) A conducting sphere of radius 20 cm is charged so that the electric field re

Question

11) A conducting sphere of radius 20 cm is charged so that the electric field reaches
3.0 X 105 V/m at its surface. What is the potential at the surface of the sphere? 12) A conducting sphere of radius 20 cm has a charge Q placed on it producing a field of magnitude E0 at its surface. More charge is added to the surface until the magnitude of the field at the surface is 2 E0. If the potential at the surface was V0 when the field was E0, what is the potential when the field is 2 E0? 11) A conducting sphere of radius 20 cm is charged so that the electric field reaches
3.0 X 105 V/m at its surface. What is the potential at the surface of the sphere? 12) A conducting sphere of radius 20 cm has a charge Q placed on it producing a field of magnitude E0 at its surface. More charge is added to the surface until the magnitude of the field at the surface is 2 E0. If the potential at the surface was V0 when the field was E0, what is the potential when the field is 2 E0?

Explanation / Answer

   Given radius of conducting sphere r =   20 cm electric field at the surface of the sphere E = 3*10^ 5 V / m         Electric potential at the surface of the sphere                E   = V / d                V = E d                      = ( 3*10^ 5 V / m ) ( 0.2 m )                    = 6*10^ 4   V potential at the surface of the sphere when the electric field is doubled                V =   2 E d                   = 12*10^ 4 V

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